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1.1x^2-3.2x-6.4=0
a = 1.1; b = -3.2; c = -6.4;
Δ = b2-4ac
Δ = -3.22-4·1.1·(-6.4)
Δ = 38.4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3.2)-\sqrt{38.4}}{2*1.1}=\frac{3.2-\sqrt{38.4}}{2.2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3.2)+\sqrt{38.4}}{2*1.1}=\frac{3.2+\sqrt{38.4}}{2.2} $
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